432=3n^2

Solution for 432=3n^2 equation:

432=3n^2

We move all terms to the left:

432-(3n^2)=0

a = -3; b = 0; c = +432;
Δ = b2-4ac
Δ = 02-4·(-3)·432
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*-3}=\frac{-72}{-6}
=+12
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*-3}=\frac{72}{-6}
=-12
$